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詳解python實(shí)現(xiàn)數(shù)據(jù)歸一化處理的方式:(0,1)標(biāo)準(zhǔn)化

 更新時(shí)間:2019年07月17日 15:21:12   作者:會(huì)呼吸的夢(mèng)  
這篇文章主要介紹了詳解python實(shí)現(xiàn)數(shù)據(jù)歸一化處理的方式:(0,1)標(biāo)準(zhǔn)化,文中通過(guò)示例代碼介紹的非常詳細(xì),對(duì)大家的學(xué)習(xí)或者工作具有一定的參考學(xué)習(xí)價(jià)值,需要的朋友們下面隨著小編來(lái)一起學(xué)習(xí)學(xué)習(xí)吧

在機(jī)器學(xué)習(xí)過(guò)程中,對(duì)數(shù)據(jù)的處理過(guò)程中,常常需要對(duì)數(shù)據(jù)進(jìn)行歸一化處理,下面介紹(0, 1)標(biāo)準(zhǔn)化的方式,簡(jiǎn)單的說(shuō),其功能就是將預(yù)處理的數(shù)據(jù)的數(shù)值范圍按一定關(guān)系“壓縮”到(0,1)的范圍類(lèi)。

通常(0, 1)標(biāo)注化處理的公式為:

即將樣本點(diǎn)的數(shù)值減去最小值,再除以樣本點(diǎn)數(shù)值最大與最小的差,原理公式就是這么基礎(chǔ)。

下面看看使用python語(yǔ)言來(lái)編程實(shí)現(xiàn)吧

import numpy as np
import matplotlib.pyplot as plt


def noramlization(data):
  minVals = data.min(0)
  maxVals = data.max(0)
  ranges = maxVals - minVals
  normData = np.zeros(np.shape(data))
  m = data.shape[0]
  normData = data - np.tile(minVals, (m, 1))
  normData = normData/np.tile(ranges, (m, 1))
  return normData, ranges, minVals


x = np.array([[78434.0829, 26829.86612], [78960.4042, 26855.13451], [72997.8308, 26543.79201],
       [74160.2849, 26499.56629], [75908.5746, 26220.11996], [74880.6989, 26196.03995],
       [74604.7169, 27096.87862], [79547.6796, 25986.68579], [74997.7791, 24021.50132],
       [74487.4915, 26040.18441], [77134.2636, 24647.274],  [74975.2792, 24067.31441],
       [76013.5305, 24566.02273], [79191.518, 26840.29867], [80653.4589, 25937.22248],
       [79185.9935, 26996.18228], [74426.881, 24227.71439], [73246.4295, 26561.59268],
       [77963.1478, 25580.05298], [74469.8778, 26082.15448], [81372.3787, 26649.69232],
       [76826.8262, 24549.77367], [77774.2608, 25999.96037], [79673.1361, 25229.04353],
       [75251.7951, 24902.72185], [78458.073, 23924.15117], [82247.5439, 29671.33493],
       [82041.2247, 27903.34268], [80083.2029, 28692.35517], [80962.0043, 28519.81002],
       [79799.8328, 28740.27736], [80743.9947, 28862.75402], [80888.449, 29724.53706],
       [81768.4638, 30180.20618], [80283.8783, 30417.55057], [79460.7078, 29092.52867],
       [75514.1202, 28071.73721], [80595.5945, 30292.25917], [80750.4876, 29651.32254],
       [80020.662, 30023.70025], [82992.3395, 29466.83067], [80185.5946, 29943.15481],
       [81854.6163, 29846.18257], [81526.4017, 30218.27078], [79174.5312, 29960.69999],
       [78112.3051, 26467.57545], [80262.4121, 29340.23218], [81284.9734, 28257.71529],
       [81928.9905, 28752.84811], [80739.2727, 29288.85126], [83135.3435, 30223.4974],
       [83131.8223, 29049.10112], [82549.9076, 28910.15209], [81574.0822, 28326.55367],
       [80507.399, 28553.56851], [82956.2103, 29157.62372], [81909.7132, 29359.24497],
       [80893.5603, 29326.64155], [82520.1272, 30424.96703], [82829.8548, 31062.24418],
       [80532.1495, 29198.10407], [80112.7963, 29143.47905], [81175.0882, 28443.10574]])

newgroup, _, _ = noramlization(x)
newdata = newgroup
plt.scatter(x[:, 0], x[:, 1], marker='*', c='r', s=24)
plt.show()
print(len(x[:, 0]))
print(len(x[:, 1]))
print(newdata)

將數(shù)據(jù)進(jìn)行歸一化處理后,并使用matplotlib繪制出處理后的散點(diǎn)圖分布如下:


可以看到數(shù)據(jù)的數(shù)值范圍均為(0,1)之間了

以上就是本文的全部?jī)?nèi)容,希望對(duì)大家的學(xué)習(xí)有所幫助,也希望大家多多支持腳本之家。

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