C語言編寫五子棋游戲
本文實(shí)例為大家分享了C語言編寫五子棋游戲的具體代碼,供大家參考,具體內(nèi)容如下
一、構(gòu)建棋盤
首先可以用一個(gè)二維數(shù)組來構(gòu)建棋盤,下標(biāo)表示位置,內(nèi)容表示黑子白子或者空位。當(dāng)數(shù)組內(nèi)容為1時(shí),該位置為白字,當(dāng)數(shù)組為0時(shí),該位置為白子,空位輸出+
int w[11][11], flag = 0;
int a, b;
for (int k = 0; k < 11; k++)
printf("第%d列\(zhòng)t", k);
printf("\n");
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (w[i][j] == 0) printf("黑\t");
else if (w[i][j] == 1) printf("白\t");
else printf("+\t");
}
printf("第%d行\(zhòng)n\n", i);
}
二、判斷位置超范圍與錯(cuò)誤輸入
當(dāng)輸入的棋子坐標(biāo)超出范圍或者該位置已經(jīng)存在棋子,則再次輸入棋子坐標(biāo)。其中flag作為標(biāo)志作為判別黑手白手的標(biāo)志。
if (flag == 0) {
printf("黑色下棋\n");
scanf("%d %d", &a, &b);
while (a < 0 || a>10 || b < 0 || b>10) {
printf("此位置超出范圍,請重新輸入:");
scanf("%d %d", &a, &b);
}
while (w[a][b] == 0 || w[a][b] == 1)
{
printf("此位置已有棋子,請重新輸入:");
scanf("%d %d", &a, &b);
}
flag = 1;
w[a][b] = 0;
}
else {
printf("白色下棋\n");
scanf("%d %d", &a, &b);
while (a < 0 || a>10 || b < 0 || b>10) {
printf("此位置超出范圍,請重新輸入:");
scanf("%d %d", &a, &b);
}
while (w[a][b] == 0 || w[a][b] == 1)
{
printf("此位置已有棋子,請重新輸入:");
scanf("%d %d", &a, &b);
}
三、判斷勝負(fù)
在五子棋中,出現(xiàn)五個(gè)棋子排成一排或者一列或者斜排即可判為勝出。每當(dāng)落下一個(gè)棋子,對該棋子前后上下斜排五個(gè)棋子進(jìn)行判別,超過五個(gè)連續(xù)的一樣顏色的棋子則勝出。
int A = 1, B = 1, jieguo = 0, C = 1, D = 1;
int x = 1, y = 1, m = 1, n = 1;
if (w[a][b] == 1) {
for (int i = 1; i < 5; i++) {
if (w[a][b + i] == 1) A++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a][b - i] == 1) A++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a+i][b] == 1) C++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b] == 1) C++;
else break;
}
if (A > 4 || C > 4) jieguo = 1;//白棋勝利標(biāo)志
else {
for (int i = 1; i < 5; i++) {
if (w[a+i][b + i] == 1) x++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a-i][b - i] == 1) x++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b-i] == 1) y++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b+i] == 1) y++;
else break;
}
if (x > 4 || y > 4) jieguo = 1;
}
}
if (w[a][b] == 0) {
for (int i = 1; i < 5; i++) {
if (w[a][b + i] == 0) B++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a][b - i] == 0) B++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b] == 0) D++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b] == 0) D++;
else break;
}
if (B > 4 || D > 4) jieguo = 2;//黑棋勝利標(biāo)志
else {
for (int i = 1; i < 5; i++) {
if (w[a + i][b + i] == 0) m++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a - i][b - i] == 0) m++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b - i] == 0) n++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b + i] == 0) n++;
else break;
}
if (m > 4 || n > 4) jieguo = 2;
}
}
程序完成
四、演示結(jié)果

五、源代碼
int main() {
int w[11][11], flag = 0;
int a, b;
while (1) {
if (flag == 0) {
printf("黑色下棋\n");
scanf("%d %d", &a, &b);
while (a < 0 || a>10 || b < 0 || b>10) {
printf("此位置超出范圍,請重新輸入:");
scanf("%d %d", &a, &b);
}
while (w[a][b] == 0 || w[a][b] == 1)
{
printf("此位置已有棋子,請重新輸入:");
scanf("%d %d", &a, &b);
}
flag = 1;
w[a][b] = 0;
}
else {
printf("白色下棋\n");
scanf("%d %d", &a, &b);
while (a < 0 || a>10 || b < 0 || b>10) {
printf("此位置超出范圍,請重新輸入:");
scanf("%d %d", &a, &b);
}
while (w[a][b] == 0 || w[a][b] == 1)
{
printf("此位置已有棋子,請重新輸入:");
scanf("%d %d", &a, &b);
}
flag = 0;
w[a][b] = 1;
}
int A = 1, B = 1, jieguo = 0, C = 1, D = 1;
int x = 1, y = 1, m = 1, n = 1;
if (w[a][b] == 1) {
for (int i = 1; i < 5; i++) {
if (w[a][b + i] == 1) A++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a][b - i] == 1) A++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a+i][b] == 1) C++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b] == 1) C++;
else break;
}
if (A > 4 || C > 4) jieguo = 1;//白棋勝利標(biāo)志
else {
for (int i = 1; i < 5; i++) {
if (w[a+i][b + i] == 1) x++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a-i][b - i] == 1) x++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b-i] == 1) y++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b+i] == 1) y++;
else break;
}
if (x > 4 || y > 4) jieguo = 1;
}
}
if (w[a][b] == 0) {
for (int i = 1; i < 5; i++) {
if (w[a][b + i] == 0) B++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a][b - i] == 0) B++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b] == 0) D++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b] == 0) D++;
else break;
}
if (B > 4 || D > 4) jieguo = 2;//黑棋勝利標(biāo)志
else {
for (int i = 1; i < 5; i++) {
if (w[a + i][b + i] == 0) m++;
else break;
}
for (int i = 1; i < 5; i++) {
if (w[a - i][b - i] == 0) m++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a + i][b - i] == 0) n++;
else break;
}
for (int i = 1; i < 5; i++)
{
if (w[a - i][b + i] == 0) n++;
else break;
}
if (m > 4 || n > 4) jieguo = 2;
}
}
for (int k = 0; k < 11; k++)
printf("第%d列\(zhòng)t", k);
printf("\n");
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (w[i][j] == 0) printf("黑\t");
else if (w[i][j] == 1) printf("白\t");
else printf("+\t");
}
printf("第%d行\(zhòng)n\n", i);
}
if (jieguo == 1) {
printf("白棋勝利");
break;
}
if (jieguo == 2) {
printf("黑棋勝利");
break;
}
}
return 0;
}
以上就是本文的全部內(nèi)容,希望對大家的學(xué)習(xí)有所幫助,也希望大家多多支持腳本之家。
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