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C++實(shí)現(xiàn)有向圖鄰接表的構(gòu)建

更新時間：2020年04月26日 14:12:19 作者：GetoWork

這篇文章主要為大家詳細(xì)介紹了C++實(shí)現(xiàn)有向圖鄰接表的構(gòu)建，文中示例代碼介紹的非常詳細(xì)，具有一定的參考價值，感興趣的小伙伴們可以參考一下

本文實(shí)例為大家分享了C++實(shí)現(xiàn)有向圖鄰接表的構(gòu)建代碼，供大家參考，具體內(nèi)容如下

數(shù)據(jù)結(jié)構(gòu)里面的一道基礎(chǔ)題，分享下自己的寫法，驗(yàn)證可跑。

#include<iostream>
#include<string>
const int MAX = 20;
using namespace std;
 
 
struct ArcNode {      //弧結(jié)點(diǎn)
 int adjvex = -1;     //所指頂點(diǎn)位置
 ArcNode *nextarc = nullptr; //下一條狐指針
 size_t info = 0;  //弧信息
};
 
 
struct VNode {      //頂點(diǎn)
 string data = "0";
 ArcNode *firstarc = nullptr; //第一條依附該頂點(diǎn)的弧的指針
};
 
 
struct Graph {      //圖結(jié)構(gòu)
 VNode vertices[MAX];         //全部頂點(diǎn)
 int vexnum, arcnum;     //頂點(diǎn)數(shù)和弧數(shù)
 Graph(int m, int n) :vexnum(m), arcnum(n) {};
 Graph() :vexnum(0), arcnum(0) {};
};
 
 
int main()
{
 int vnum, anum, tempanum = 0;
 cout << "輸入頂點(diǎn)數(shù)：";
 cin >> vnum;
 cout << "輸入弧數(shù)：";
 cin >> anum;
 cout << "\n\n";
 Graph G(vnum, anum);
 for (int i = 0; i != vnum; ++i) {
 cout << "輸入結(jié)點(diǎn)" << i << "的信息：";
 cin >> G.vertices[i].data;
 if (tempanum != anum)
  cout << "輸入依靠此結(jié)點(diǎn)的弧的信息（輸入-1以停止）：\n";
 else
  cout << "已輸入所有弧的信息！\n";
 bool first = true;
 ArcNode *p, *temp;
 for (int j = 0; (j != anum) && (tempanum != vnum); ++j) {
  int pointto;
  cout << "輸入弧" << tempanum << "所指向的頂點(diǎn)位置：";
  cin >> pointto;
  if (pointto == -1) break;
  else {
  ++tempanum;
  if (first == true) {
   first = false;
   G.vertices[i].firstarc = new ArcNode;
   G.vertices[i].firstarc->adjvex = pointto;
   p = G.vertices[i].firstarc;
  }
  else {
   temp = new ArcNode;
   temp->adjvex = pointto;
   p->nextarc = temp;
   p = temp;
  }
  }
 }
 cout << endl;
 }
 
 for (int i = 0; i != anum; ++i) {
 cout << "頂點(diǎn)" << i << ": |" << G.vertices[i].data << "|";
 if (G.vertices[i].firstarc) {
  cout << " -> " << G.vertices[i].firstarc->adjvex;
  auto pt = G.vertices[i].firstarc->nextarc;
  while (pt) {
  cout << " -> " << pt->adjvex;
  pt = pt->nextarc;
  }
  cout << "-> ^";
 }
 else
  cout << " -> ^";
 cout << endl;
 }
 return 0;
}