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Python sorted對(duì)list和dict排序

更新時(shí)間：2020年06月09日 11:43:03 作者：Spade_

這篇文章主要介紹了Python sorted對(duì)list和dict排序，文中通過(guò)示例代碼介紹的非常詳細(xì)，對(duì)大家的學(xué)習(xí)或者工作具有一定的參考學(xué)習(xí)價(jià)值，需要的朋友們下面隨著小編來(lái)一起學(xué)習(xí)學(xué)習(xí)吧

sorted語(yǔ)法

sorted(iterable, key=None, reverse=False)

參數(shù)說(shuō)明：

- iterable -- 可迭代對(duì)象。
- key --主要是用來(lái)進(jìn)行比較的元素，只有一個(gè)參數(shù)，具體的函數(shù)的參數(shù)就是取自于可迭代對(duì)象中，指定可迭代對(duì)象中的一個(gè)元素來(lái)進(jìn)行排序。
- reverse -- 排序規(guī)則，reverse = True 降序， reverse = False 升序（默認(rèn)）。

返回：
- 一個(gè)新list對(duì)象

sorted對(duì)字典dict排序

①按鍵key排序

from operator import itemgetter
dict = {3: 'B', 1: 'A', 2: 'C'}

# 按key升序  .items()取得3個(gè)(key,value)
# lambda x: x[0]取(key,value)的key  即(3,1,2)
d1 = sorted(dict.items(), key=lambda x: x[0], reverse=False) # <class 'list'>

# 按key降序  itemgetter類似lambda
d2 = sorted(dict.items(), key=itemgetter(0), reverse=True) # <class 'list'>

# 輸出
print(d1, type(d1)) # [(1, 'A'), (2, 'C'), (3, 'B')] <class 'list'>
print(d2, type(d2)) # [(3, 'B'), (2, 'C'), (1, 'A')] <class 'list'>

[(1, ‘A'), (2, ‘C'), (3, ‘B')] <class ‘list'>
[(3, ‘B'), (2, ‘C'), (1, ‘A')] <class ‘list'>

②按值value排序

from operator import itemgetter
dict = {3: 'B', 1: 'A', 2: 'C'}

# 按value升序  .items()取得3個(gè)(key,value)
# lambda x: x[1]取(key,value)的value  即('B','A','C')
d3 = sorted(dict.items(), key=lambda x: x[1], reverse=False) # <class 'list'>

# 按value降序  itemgetter類似lambda
d4 = sorted(dict.items(), key=itemgetter(1), reverse=True) # <class 'list'>

print(d3, type(d3)) # [(1, 'A'), (3, 'B'), (2, 'C')] <class 'list'>
print(d4, type(d4)) # [(2, 'C'), (3, 'B'), (1, 'A')] <class 'list'>

[(1, ‘A'), (3, ‘B'), (2, ‘C')] <class ‘list'>
[(2, ‘C'), (3, ‘B'), (1, ‘A')] <class ‘list'>

sorted排序list

①按一種規(guī)則排序list

from operator import itemgetter
data = [('c', 3, 'Apple'), ('d', 1, 'Cat'), ('a', 2, 'Banana')]
# 根據(jù)字母升序
print(sorted(data, key=lambda x: x[0], reverse=False)) # <class 'list'>
# 根據(jù)數(shù)字升序
print(sorted(data, key=lambda x: x[1], reverse=False)) # <class 'list'>
# 根據(jù)單詞升序
print(sorted(data, key=lambda x: x[2], reverse=False)) # <class 'list'>

[('a', 2, 'Banana'), ('c', 3, 'Apple'), ('d', 1, 'Cat')]
[('d', 1, 'Cat'), ('a', 2, 'Banana'), ('c', 3, 'Apple')]
[('c', 3, 'Apple'), ('a', 2, 'Banana'), ('d', 1, 'Cat')]

②按多種規(guī)則排序list

# 先按照成績(jī)降序排序，相同成績(jī)的按照名字升序排序：
d1 = [{'name':'alice', 'score':38}, {'name':'bob', 'score':18}, {'name':'darl', 'score':28}, {'name':'christ', 'score':28}]
l = sorted(d1, key=lambda x:(-x['score'], x['name']))
print(l)

[{'name': 'alice', 'score': 38}, {'name': 'christ', 'score': 28}, {'name': 'darl', 'score': 28}, {'name': 'bob', 'score': 18}]

sorted排序list和dict的混合

先看看我們排序的有哪些類型的數(shù)據(jù)結(jié)構(gòu)

#### 二維list排序
l1 = [['Bob', 95.00, 'A'], ['Alan', 86.0, 'C'], ['Mandy', 82.5, 'A'], ['Rob', 86, 'E']]

#### list中混合字典
l2 = [{'name':'alice', 'score':38}, {'name':'bob', 'score':18}, {'name':'darl', 'score':28}, {'name':'christ', 'score':28}]

#### 字典中混合list
d1 = {'Li': ['M', 7], 'Zhang': ['E', 2], 'Wang': ['P', 3], 'Du': ['C', 2], 'Ma': ['C', 9], 'Zhe': ['H', 7]}

#### 對(duì)字典中的多維list進(jìn)行排序
d2 = {
  'Apple': [['44', 88], ['11', 33], ['22', 88]],
  'Banana': [['55', 43], ['11', 68], ['44', 22]],
  'Orange':[['22', 22], ['55', 41], ['44', 42], ['33', 22]]
}

二維list排序

from operator import itemgetter
l1 = [['Bob', 95.00, 'A'], ['Alan', 86.0, 'C'], ['Mandy', 82.5, 'A'], ['Rob', 86, 'E']]
# 按先按成績(jī)號(hào)升序，再按成績(jī)數(shù)值升序
print(sorted(l1, key=itemgetter(2, 1), reverse=False))
# 按先按成績(jī)號(hào)升序，再按成績(jī)數(shù)值降序序
print(sorted(l1, key=lambda x:(x[2], -x[1]), reverse=False))

[[‘Mandy', 82.5, ‘A'], [‘Bob', 95.0, ‘A'], [‘Alan', 86.0, ‘C'], [‘Rob', 86, ‘E']]
[[‘Bob', 95.0, ‘A'], [‘Mandy', 82.5, ‘A'], [‘Alan', 86.0, ‘C'], [‘Rob', 86, ‘E']]

2. list中混合字典

from operator import itemgetter
# 先按照成績(jī)降序排序，相同成績(jī)的按照名字升序排序：
l2 = [{'name':'alice', 'score':38}, {'name':'bob', 'score':18}, {'name':'darl', 'score':28}, {'name':'christ', 'score':28}]
print(sorted(l2, key=lambda x:(-x['score'], x['name'])))
print(sorted(l2, key=itemgetter('score', 'name')))

[{‘name': ‘a(chǎn)lice', ‘score': 38}, {‘name': ‘christ', ‘score': 28}, {‘name': ‘darl', ‘score': 28}, {‘name': ‘bob', ‘score': 18}]
[{‘name': ‘bob', ‘score': 18}, {‘name': ‘christ', ‘score': 28}, {‘name': ‘darl', ‘score': 28}, {‘name': ‘a(chǎn)lice', ‘score': 38}]

3. 字典中混合list

d1 = {'Li': ['M', 7], 'Zhang': ['E', 2], 'Wang': ['P', 3], 'Du': ['C', 2], 'Ma': ['C', 9], 'Zhe': ['H', 7]}
# sort返回的是list，如果需要轉(zhuǎn)為dict，再sorted前面套一個(gè)dict()就可以了
print(sorted(d1.items(), key=lambda x:(x[1][1], -ord(x[1][0]) ))) # 對(duì)字符比較需要ord。如果是'123'字符串?dāng)?shù)字可以使用int。
# print(sorted(d1.items(), key=lambda x:(x[1][1], -ord(x[1][0]) )))

[(‘Zhang', [‘E', 2]), (‘Du', [‘C', 2]), (‘Wang', [‘P', 3]), (‘Li', [‘M', 7]), (‘Zhe', [‘H', 7]), (‘Ma', [‘C', 9])]

4. 對(duì)字典中的多維list進(jìn)行排序

d2 = {
  'Apple': [['44', 88], ['11', 33], ['22', 88]],
  'Banana': [['55', 43], ['11', 68], ['44', 22]],
  'Orange':[['22', 22], ['55', 41], ['44', 42], ['33', 22]]
}
for key, value in d2.items():
  d2[key] = sorted(value, key=lambda x:(x[1], -int(x[0]))) # 按list第二列升序，相同則按第一列降序，參考二維list排序
print(d2)

{‘Apple': [[‘11', 33], [‘44', 88], [‘22', 88]], ‘Banana': [[‘44', 22], [‘55', 43], [‘11', 68]], ‘Orange': [[‘33', 22], [‘22', 22], [‘52', 41], [‘44', 42]]}

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