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java如何獲取map中value的最大值

更新時(shí)間：2023年05月26日 10:27:03 作者：wuzi_uzi

這篇文章主要介紹了java如何獲取map中value的最大值問題，具有很好的參考價(jià)值，希望對(duì)大家有所幫助。如有錯(cuò)誤或未考慮完全的地方，望不吝賜教

java獲取map中value最大值

  public static void main(String[] args) throws InterruptedException {
        Map<Integer, Integer> map = new HashMap<>();
        map.put(1,1);
        map.put(2,2);
        map.put(3,3);
        map.put(4,4);
        System.out.println(getMaxValue(map));
    }
    /**
     * 求Map<K,V>中Value(值)的最小值
     *
     * @param map
     * @return
     */
    public static Object getMinValue(Map<Integer, Integer> map) {
        if (map == null)
            return null;
        Collection<Integer> c = map.values();
        Object[] obj = c.toArray();
        Arrays.sort(obj);
        return obj[0];
    }
    /**
     * 求Map<K,V>中Value(值)的最大值
     *
     * @param map
     * @return
     */
    public static Object getMaxValue(Map<Integer, Integer> map) {
        if (map == null)
            return null;
        int length =map.size();
        Collection<Integer> c = map.values();
        Object[] obj = c.toArray();
        Arrays.sort(obj);
        return obj[length-1];
    }

根據(jù)value對(duì)Map進(jìn)行排序得到最大值

import java.util.*;
public class treeMap {
    static String key1 ="";
    static Integer vlue1 ;
    public static void main(String [] arg){
        Map<String,Integer> map = new TreeMap<>();
        map.put("1",2);
        map.put("2",4);
        map.put("3",5);
        map.put("4",12);
        map.put("5",23);
        map.put("6",65);
        map.put("7",1);
        map.put("8",10);
       Map<String , Integer> map1 = new HashMap<>();
        map1 = sortMapByValue(map);
        for (String key : map1.keySet()) {
            key1 =key;
            vlue1=map1.get(key);
            System.out.println("key= "+ key + " and value= " + map1.get(key));
        }
        System.out.println("方位號(hào)："+key1+"\n 距離："+vlue1);
    }
    public static Map<String, Integer> sortMapByValue(Map<String, Integer> oriMap) {
         class MapValueComparator implements Comparator<Map.Entry<String, Integer>> {
            @Override
            public int compare(Map.Entry<String, Integer> me1, Map.Entry<String, Integer> me2) {
                return me1.getValue().compareTo(me2.getValue());
            }
        }
        if (oriMap == null || oriMap.isEmpty()) {
            return null;
        }
        Map<String, Integer> sortedMap = new LinkedHashMap<String, Integer>();
        List<Map.Entry<String, Integer>> entryList = new ArrayList<Map.Entry<String, Integer>>(
                oriMap.entrySet());
        Collections.sort(entryList, new MapValueComparator());
        Iterator<Map.Entry<String, Integer>> iter = entryList.iterator();
        Map.Entry<String, Integer> tmpEntry = null;
        while (iter.hasNext()) {
            tmpEntry = iter.next();
            sortedMap.put(tmpEntry.getKey(), tmpEntry.getValue());
        }
        return sortedMap;
    }
}

獲取Map最大value以及對(duì)應(yīng)的key

import  java.util.Arrays;
import  java.util.Collection;
import  java.util.HashMap;
import  java.util.Map;
import  java.util.Set;
public  class  MaxMapDemo {
public  static  void  main(String[] args) {
Map<Integer, Integer> map =  new  HashMap<Integer, Integer>();
map.put( 1 ,  8 );
map.put( 3 ,  12 );
map.put( 5 ,  53 );
map.put( 123 ,  33 );
map.put( 42 ,  11 );
map.put( 44 ,  42 );
map.put( 15 ,  3 );
System.out.println(getMaxKey(map));
System.out.println(getMaxValue(map));
}
/**
* 求Map<K,V>中Key(鍵)的最大值
* @param map
* @return
*/
public  static  Object getMaxKey(Map<Integer, Integer> map) {
if  (map ==  null )  return  null ;
Set<Integer> set = map.keySet();
Object[] obj = set.toArray();
Arrays.sort(obj);
return  obj[obj.size()- 1 ];
}
/**
* 求Map<K,V>中Value(值)的最大值
* @param map
* @return
*/
public  static  Object getMaxValue(Map<Integer, Integer> map) {
if  (map ==  null )  return  null ;
Collection<Integer> c = map.values();
Object[] obj = c.toArray();
Arrays.sort(obj);
return  obj[obj.size()- 1 ];
}
}