java 8 lambda表達(dá)式list操作分組、過(guò)濾、求和、最值、排序、去重代碼詳解
java8的lambda表達(dá)式提供了一些方便list操作的方法,主要涵蓋分組、過(guò)濾、求和、最值、排序、去重。跟之前的傳統(tǒng)寫(xiě)法對(duì)比,能少寫(xiě)不少代碼。
新建實(shí)體類
package com.vvvtimes.vo;
import java.math.BigDecimal;
import java.util.Date;
public class User {
private Long id;
//姓名
private String name;
//年齡
private int age;
//工號(hào)
private String jobNumber;
//性別
private String sex;
//入職日期
private Date entryDate;
//家庭成員數(shù)量
private BigDecimal familyMemberQuantity;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public String getJobNumber() {
return jobNumber;
}
public void setJobNumber(String jobNumber) {
this.jobNumber = jobNumber;
}
public String getSex() {
return sex;
}
public void setSex(String sex) {
this.sex = sex;
}
public Date getEntryDate() {
return entryDate;
}
public void setEntryDate(Date entryDate) {
this.entryDate = entryDate;
}
public BigDecimal getFamilyMemberQuantity() {
return familyMemberQuantity;
}
public void setFamilyMemberQuantity(BigDecimal familyMemberQuantity) {
this.familyMemberQuantity = familyMemberQuantity;
}
}1.分組
通過(guò)groupingBy可以分組指定字段
//分組
Map<String, List<User>> groupBySex = userList.stream().collect(Collectors.groupingBy(User::getSex));
//遍歷分組
for (Map.Entry<String, List<User>> entryUser : groupBySex.entrySet()) {
String key = entryUser.getKey();
List<User> entryUserList = entryUser.getValue();
}上門(mén)的分組存在key空值安全問(wèn)題,需要做過(guò)濾或封裝處理
用Optional封裝使用中會(huì)報(bào)No value present
//分組添加累計(jì)
Map<Optional<Long>, List<SalesOrderMonthlyStatementVo>> groupMap = list.stream().collect(Collectors.groupingBy(x -> Optional.ofNullable(x.getReviewerGroupId())));
//遍歷分組
for (Map.Entry<Optional<Long>, List<SalesOrderMonthlyStatementVo>> entryGroup : groupMap.entrySet()) {
Optional<Long> key = entryGroup.getKey();
Long groupId = key.get();
List<SalesOrderMonthlyStatementVo> entryGroupList = entryGroup.getValue();
}正確使用方法如下,自定義groupingBy_WithNullKeys
/** Like Collectors.groupingBy, but accepts null keys. */
public static <T, A> Collector<T, ?, Map<A, List<T>>>
groupingBy_WithNullKeys(Function<? super T, ? extends A> classifier) {
return Collectors.toMap(
classifier,
Collections::singletonList,
(List<T> oldList, List<T> newEl) -> {
List<T> newList = new ArrayList<>(oldList.size() + 1);
newList.addAll(oldList);
newList.addAll(newEl);
return newList;
});
}然后調(diào)用
Map<Long, List<SalesOrderMonthlyStatementVo>> groupMap = list.stream().collect(groupingBy_WithNullKeys(x -> x.getReviewerGroupId()));
多字段分組
Function<WarehouseReceiptLineBatch, List<Object>> compositeKey = wlb ->
Arrays.<Object>asList(wlb.getWarehouseReceiptLineId(), wlb.getWarehouseAreaId(), wlb.getWarehouseLocationId());
Map<Object, List<WarehouseReceiptLineBatch>> map =
warehouseReceiptLineBatchList.stream().collect(Collectors.groupingBy(compositeKey, Collectors.toList()));
//遍歷分組
for (Map.Entry<Object, List<WarehouseReceiptLineBatch>> entryUser : map.entrySet()) {
List<Object> key = (List<Object>) entryUser.getKey();
List<WarehouseReceiptLineBatch> entryUserList = entryUser.getValue();
Long warehouseReceiptLineId = (Long) key.get(0);
Long warehouseAreaId = (Long) key.get(1);
Long warehouseLocationId = (Long) key.get(2);
}2.過(guò)濾
通過(guò)filter方法可以過(guò)濾某些條件
//過(guò)濾
//排除掉工號(hào)為201901的用戶
List<User> userCommonList = userList.stream().filter(a -> !a.getJobNumber().equals("201901")).collect(Collectors.toList());3.求和
分基本類型和大數(shù)類型求和,基本類型先mapToInt,然后調(diào)用sum方法,大數(shù)類型使用reduce調(diào)用BigDecimal::add方法
//求和
//基本類型
int sumAge = userList.stream().mapToInt(User::getAge).sum();
//BigDecimal求和
BigDecimal totalQuantity = userList.stream().map(User::getFamilyMemberQuantity).reduce(BigDecimal.ZERO, BigDecimal::add);上面的求和不能過(guò)濾bigDecimal對(duì)象為null的情況,可能會(huì)報(bào)空指針,這種情況,我們可以用filter方法過(guò)濾,或者重寫(xiě)求和方法
重寫(xiě)求和方法
package com.vvvtimes.util;
import java.math.BigDecimal;
public class BigDecimalUtils {
public static BigDecimal ifNullSet0(BigDecimal in) {
if (in != null) {
return in;
}
return BigDecimal.ZERO;
}
public static BigDecimal sum(BigDecimal ...in){
BigDecimal result = BigDecimal.ZERO;
for (int i = 0; i < in.length; i++){
result = result.add(ifNullSet0(in[i]));
}
return result;
}
}使用重寫(xiě)的方法
BigDecimal totalQuantity2 = userList.stream().map(User::getFamilyMemberQuantity).reduce(BigDecimal.ZERO, BigDecimalUtils::sum);
判斷對(duì)象空
stream.filter(x -> x!=null)
stream.filter(Objects::nonNull)
判斷字段空
stream.filter(x -> x.getDateTime()!=null)
4.最值
求最小與最大,使用min max方法
//最小
Date minEntryDate = userList.stream().map(User::getEntryDate).min(Date::compareTo).get();
//最大
Date maxEntryDate = userList.stream().map(User::getEntryDate).max(Date::compareTo).get();有時(shí)候我們需要知道最大最小對(duì)應(yīng)的這個(gè)對(duì)象,我們可以通過(guò)如下方法獲取
Comparator<LeasingBusinessContract> comparator = Comparator.comparing(LeasingBusinessContract::getLeaseEndDate); LeasingBusinessContract maxObject = leasingBusinessContractList.stream().max(comparator).get();
5.List 轉(zhuǎn)map
/**
* List -> Map
* 需要注意的是:
* toMap 如果集合對(duì)象有重復(fù)的key,會(huì)報(bào)錯(cuò)Duplicate key ....
* user1,user2的id都為1。
* 可以用 (k1,k2)->k1 來(lái)設(shè)置,如果有重復(fù)的key,則保留key1,舍棄key2
*/
Map<Long, User> userMap = userList.stream().collect(Collectors.toMap(User::getId, a -> a,(k1,k2)->k1));list轉(zhuǎn)map的時(shí)候有時(shí)候會(huì)將date類型作為key,實(shí)際情況中使用string的多,我們可以將某個(gè)字段轉(zhuǎn)成string
Map<String, WorkCenterLoadVo> workCenterMap = list.stream().collect(Collectors.toMap(key->DateFormatUtils.format(key.getDate(), "yyyy-MM-dd"), a -> a,(k1,k2)->k1));
list轉(zhuǎn)map有時(shí)候會(huì)用到多字段key的map結(jié)構(gòu),除了常用的key用字符串連接,也可以使用apache commons的多字段key形式的map結(jié)構(gòu)MultiKeyMap
6.排序
可通過(guò)Sort對(duì)單字段多字段排序
//排序
//單字段排序,根據(jù)id排序
userList.sort(Comparator.comparing(User::getId));
//多字段排序,根據(jù)id,年齡排序
userList.sort(Comparator.comparing(User::getId).thenComparing(User::getAge));實(shí)際上這個(gè)寫(xiě)法存在空值安全問(wèn)題,建議改成
userList.sort(Comparator.comparing(User::getId,Comparator.nullsLast(Comparator.naturalOrder())).thenComparing(User::getAge,Comparator.nullsLast(Comparator.naturalOrder())));
7.去重
可通過(guò)distinct方法進(jìn)行去重
//去重
List<Long> idList = new ArrayList<Long>();
idList.add(1L);
idList.add(1L);
idList.add(2L);
List<Long> distinctIdList = idList.stream().distinct().collect(Collectors.toList());針對(duì)屬性去重
List<AddOutboundNoticeDetailsBatchVo> entryDetailsBatchDistinctBatchIdList = entryDetailsBatchList.stream().filter(distinctByKey(b -> b.getMaterialBatchNumberId())).collect(Collectors.toList());
//distinctByKey自己定義
public static <T> Predicate<T> distinctByKey(Function<? super T, Object> keyExtractor) {
Map<Object, Boolean> seen = new ConcurrentHashMap<>();
return t -> seen.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;
}8.獲取list某個(gè)字段組裝新list
//獲取list對(duì)象的某個(gè)字段組裝成新list
List<Long> userIdList = userList.stream().map(a -> a.getId()).collect(Collectors.toList());9.批量設(shè)置list列表字段為同一個(gè)值
addList.stream().forEach(a -> a.setDelFlag("0"));10.不同實(shí)體的list拷貝
List<TimePeriodDate> timePeriodDateList1 = calendarModelVoList.stream().map(p->{TimePeriodDate e = new TimePeriodDate(); e.setStartDate(p.getBegin());e.setEndDate(p.getEnd()); return e;}).collect(Collectors.toList());到此這篇關(guān)于java 8 lambda表達(dá)式list操作分組、過(guò)濾、求和、最值、排序、去重的文章就介紹到這了,更多相關(guān)java 8 lambda表達(dá)式list內(nèi)容請(qǐng)搜索腳本之家以前的文章或繼續(xù)瀏覽下面的相關(guān)文章希望大家以后多多支持腳本之家!
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